Մաթեմատիկա 22.02.2023

246 Ա) f(x)=sin2x T=π f(x+T)=f(x) ? f(x+T)=sin2(x+T)=sin2(x+π)=sin(2x+2π) =sin2x=f(x) b) f(x)=cos x/3 T=6π f(x+T)= f(x) f(x+T)= cos((x+6π)/3)= cos (x/3+2π) =cos x/3= f(x) d) f(x)=2ctg x/2 T=2π f(x+T)=f(x) f(x+T)=2 ctg (x/2+π)= 2ctg x/2=f(x) e) f(x)= sinx+ctg x T=2π f(x+T)= sin(x+ 2π) + ctg (x+2π) = sin x+ctg x = f(x)

7.12.22

152 A) a=22.5° sin22,5°-? tg22.5°-? cos22.5°-? sin22,5°= sin45°/2= ± √ 1-cos45°/2= ±√ 1-(√2/2)/2= ±√2-√2/4 sin22,5°=(√2-√2)/2 Cos 22,5°= +√((1+ 45°)/2)= √(2+√2)/2 tg22,5°= √1-cos45°/1+cos45°= √2-√2/2+√2 a=165° sin165°= √1-cos330°/2= √1-cos(360°-30°)/2= √1-cos30°/2=√((1-√3/2)/2)= √((2-√3)/4)=√2-√3/2 cos165°=-√(1+cos330°/2=-√((2+√3)/2) 153 A) cosa+sina×tga/2 = cosa+sina × (Sina/1-cosa)= cosa+1-cosa=1 b) cosa -sina×ctga/2= cosa-sina× 1+cosa/Sina= cosA-(1+cosa)=cosa-1-cosa=-1 d)2sin²a/2+cosa= 2sin²a/2+1-2sin²a/2=1 L

Մաթեմատիկա 30.11.22

Cos²a=cos²a-sin²a cos²a=1-2sin²a cos²a=2cos²a-1 sin2a=2sinacosa tg2a=2tga/1-tg²a ctg2a=ctg²a-1/2ctga sin²a=1-cos2a/2 cos²a=1+cos2a/2 138 a) sin2a/Sina= 2sinacosa/sina = 2cosa b) sin2a/2cos²a= 2sinacosa/2cos²a= sinacosa/cos²a= sina/cosa= tga c) sin2a/sina-cosa= (2sinacosa/sina)-cosa= 2cosa-cosa= cosa d) cos2a-cos²a= cos²a-sin²a -cos²a = -sin²a e) sin²a+cos2a=sin²a+ cos²a- sin²a= cos²a f) sin²a-cos²a= -(cos²a-sin²a)=-cos2a 139 a) 2sin(π/12)cos(π/12)= sin2 (π/12)=sin (π/6)= sin30°=1/2 b) cos²15°-sin²15°= cos30°=√3/2

Մաթեմատիկա 23.11.22

112. a) sin a=9/41 π/2<a<π 90°<a<180° a€II Cosa-? sin²a+cos²a=1 (9/41)²+cos²=1 81/1681+cos²a=1 Cos²a=1-81/1681 cos²a=1600/1681 Cosa=±40/41 Cosa= -40/41 117 A) sin(π/2-a)=sin(90-a)=cosa B) tg(90-a) = ctg a c) cos(π/2-a)= cos(90-a) = sina d) ctg (a- π)= ctg (a-180)= ctg (-(180°-a)) = -ctg(180-a)= ctga E) tg(a-π)=tg (a-180)=tg(-(180-a))=-tg(180-a)=tga f) sin(a-3/2π)= sin (a-3/2×180)= sin (-(270-a))= -sin(270-a)= cosa g) cos (π+a)= cos(180+a)=Continue reading “Մաթեմատիկա 23.11.22”

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